limit as w approaches 0 of (1-cos(5w))/w

Lösung

w \to 0 lim (\frac{1 - cos ( 5 w )}{w})

0

Schritte zur Lösung

w \to 0 lim (\frac{1 - cos ( 5 w )}{w})

Wende das L'Hopital Theorem an

= w \to 0 lim (\frac{5 sin ( 5 w )}{1})

Setze den Wert

w = 0

ein

= \frac{5 sin ( 5 \cdot 0 )}{1}

Vereinfache

\frac{5 sin ( 5 \cdot 0 )}{1} : 0

= 0

\int_{1}^{2} (4 x^{3} - 6 x) d x

\int_{0}^{x} (2 x - y) d y

\int (1 + 3 x)^{2} d x

n = 1 \sum \infty arctan (15 n)

t an g e n t f (x) = 6 x^{2} + 6, at x = - 2