integral from 0 to 4 of (64sqrt(x)-8x^2)

Lösung

\int_{0}^{4} (64 x - 8 x^{2}) d x

\frac{512}{3}

Dezimale

170.66666 \dots

Schritte zur Lösung

\int_{0}^{4} 64 x - 8 x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 64 x d x - \int_{0}^{4} 8 x^{2} d x

\int_{0}^{4} 64 x d x = \frac{1024}{3}

\int_{0}^{4} 8 x^{2} d x = \frac{512}{3}

= \frac{1024}{3} - \frac{512}{3}

Vereinfache

\frac{1024}{3} - \frac{512}{3} : \frac{512}{3}

= \frac{512}{3}

\int \frac{2 x - 8}{1 - x - x ^{2}} d x

\frac{\partial}{\partial y} (x ln (x y - 5))

\int_{0}^{9} (\frac{1}{3} x - 2) d x

(5 + x) y^{^{'}} - y = 0

\int u - 1 d u