(x+1/x)^'

Lösung

(x + \frac{1}{x})^{^{'}}

1 - \frac{1}{x ^{2}}

Schritte zur Lösung

(x + \frac{1}{x})^{'}

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x^{^{'}} + (\frac{1}{x})^{^{'}}

x^{'} = 1

(\frac{1}{x})^{'} = - \frac{1}{x ^{2}}

= 1 - \frac{1}{x ^{2}}

d er i v a t i v e [x + (x + sin^{2} (x))^{3}]^{5}

\frac{d}{d x} (\frac{ln ( x + 1 )}{4 x + 2})

\int sec^{3} (4 x) d x

\frac{d}{d x} (1 \frac{1}{x})

\frac{d}{d x} ((3 x + 1)^{6} 2 x - 5)