integral of (x^{1/3}-3^{1/3})

Lösung

\int (x^{\frac{1}{3}} - 3^{\frac{1}{3}}) d x

\frac{3}{4} x^{\frac{4}{3}} - 3^{\frac{1}{3}} x + C

Schritte zur Lösung

\int x^{\frac{1}{3}} - 3^{\frac{1}{3}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{\frac{1}{3}} d x - \int 3^{\frac{1}{3}} d x

\int x^{\frac{1}{3}} d x = \frac{3}{4} x^{\frac{4}{3}}

\int 3^{\frac{1}{3}} d x = 3^{\frac{1}{3}} x

= \frac{3}{4} x^{\frac{4}{3}} - 3^{\frac{1}{3}} x

Füge eine Konstante zur Lösung hinzu

= \frac{3}{4} x^{\frac{4}{3}} - 3^{\frac{1}{3}} x + C

\frac{d}{d x} (x^{9} ln (7 x))

n = 1 \sum \infty \frac{1}{4 n ^{2} + 5}

d er i v a t i v e y = 9

t an g e n t f (x) = \frac{x + 1}{x + 3}

x \to 0 - lim (\frac{1}{x ^{3} - 2 x ^{2}})