(dy)/(dx)=x

Lösung

\frac{d y}{d x} = x

y = \frac{x ^{2}}{2} + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = x

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = x

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int x d x

\int x d x = \frac{x ^{2}}{2} + c_{1}

y = \frac{x ^{2}}{2} + c_{1}

\frac{\partial}{\partial y} (e^{x} + cos (y))

\int \frac{1}{x ln ( x ) - x} d x

\frac{\partial}{\partial x} (x e^{y} - e^{z})

im pl i c i t \frac{d y}{d x}, y e^{x} = y

\frac{d}{d x} ((3 x + 1) \frac{( x ^{2} + 4 )}{( 6 x - 5 )})