derivative of 5*tan(2x^3+2/(x^2))

Lösung

\frac{d}{d x} (5 \cdot tan (2 x^{3}) + \frac{2}{x ^{2}})

30 x^{2} sec^{2} (2 x^{3}) - \frac{4}{x ^{3}}

Schritte zur Lösung

\frac{d}{d x} (5 tan (2 x^{3}) + \frac{2}{x ^{2}})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 tan (2 x^{3})) + \frac{d}{d x} (\frac{2}{x ^{2}})

\frac{d}{d x} (5 tan (2 x^{3})) = 30 x^{2} sec^{2} (2 x^{3})

\frac{d}{d x} (\frac{2}{x ^{2}}) = - \frac{4}{x ^{3}}

= 30 x^{2} sec^{2} (2 x^{3}) - \frac{4}{x ^{3}}

\frac{d}{d x} ((x + 3) e^{6 x})

\frac{\partial}{\partial x} ((x + y^{2}) \cdot e^{- 4 x + 2 y})

im pl i c i t \frac{d y}{d x}, y = (9 + x)^{\frac{1}{x}}

x \to 5 lim ((34 - x^{2}) x)

\int (e^{- x} - e^{2}) (e^{x} + e^{- 5}) d x