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Popular >

distance (-3,0),(-7,-5)

Solution

distance

(- 3, 0), (- 7, - 5)

Solution

41

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(- 3, 0)

and

(- 7, - 5)

is

= (- 7 - (- 3))^{2} + (- 5 - 0)^{2}

Simplify

= 41

Popular Examples

domain of (x/(2x^2-5))/(sqrt(x))domain

\frac{\frac{x}{2 x ^{2} - 5}}{x}

critical f(x)=x^3+3x^2-72x critical points

f (x) = x^{3} + 3 x^{2} - 72 x

inverse of 8x^4-8x^2+1 inverse

8 x^{4} - 8 x^{2} + 1

domain of 1 domain

1

midpoint (-4,-5),(-5,5)midpoint

(- 4, - 5), (- 5, 5)

Frequently Asked Questions (FAQ)

What is the distance (-3,0),(-7,-5) ?
The distance (-3,0),(-7,-5) is square root of 41