What is the range of f(x)=3+sqrt(x-2) ?

The range of f(x)=3+sqrt(x-2) is f(x)>= 3

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range of f(x)=3+sqrt(x-2)

range

f (x) = 3 + x - 2

f (x) \geq 3

Interval Notation

[3, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 3

f (x) \geq 3

3 x - 2 y = 16

f (x) = - 4 x - 7

\frac{2}{5} x^{5} - 14 x^{3} + 15

p (t) = 3 t^{2} + 12 t

2 x - 5

What is the range of f(x)=3+sqrt(x-2) ?
The range of f(x)=3+sqrt(x-2) is f(x)>= 3