What is the perpendicular y=3x-1,(3,2) ?

The perpendicular y=3x-1,(3,2) is y=-1/3 x+3

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perpendicular y=3x-1,(3,2)

perpendicular

y = 3 x - 1, (3, 2)

y = - \frac{1}{3} x + 3

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x - 1

that passes through

(3, 2)

Find the slope of

y = 3 x - 1 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(3, 2) : y = - \frac{1}{3} x + 3

y = - \frac{1}{3} x + 3

f (x) = \frac{- 9 - 7 x}{3}

\frac{( 5 + 3 x )}{2}

f (x) = sec (\frac{3 x}{5})

f (x) = x - 2 \frac{1}{2}

\frac{1}{x} - 1

What is the perpendicular y=3x-1,(3,2) ?
The perpendicular y=3x-1,(3,2) is y=-1/3 x+3