What is the domain of (sqrt(x))/(2x-5) ?

The domain of (sqrt(x))/(2x-5) is 0 5/2

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domain of (sqrt(x))/(2x-5)

domain

\frac{x}{2 x - 5}

0 \leq x < \frac{5}{2} or x > \frac{5}{2}

Interval Notation

[0, \frac{5}{2}) \cup (\frac{5}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{5}{2}

Combine real regions and undefined points for final function domain

0 \leq x < \frac{5}{2} or x > \frac{5}{2}

y = 6 x - 1

2 x^{4} - 30 x^{2}

8 x - 4 y = 16

(1 - 6) (3 - 2)

\frac{1}{3} x^{3} + 3 x^{2} + 5 x

What is the domain of (sqrt(x))/(2x-5) ?
The domain of (sqrt(x))/(2x-5) is 0<= x< 5/2 \lor x> 5/2