What is the critical f(x)=(x-5)^{4/5} ?

The critical f(x)=(x-5)^{4/5} is x=5

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critical f(x)=(x-5)^{4/5}

critical points

f (x) = (x - 5)^{\frac{4}{5}}

x = 5

Solution steps

(x - 5)^{\frac{4}{5}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 5

Identify critical points not in

f (x)

domain

Domain of

(x - 5)^{\frac{4}{5}} : - \infty < x < \infty

All critical points are in domain

x = 5

f (x) = 5 - x + 6 + x

f (x) = 4 sin (2 x - \frac{π}{3}) + 1

\frac{3 x}{x + 2}

f (x) = x^{2} - 11, x \geq 0

f (x) = \frac{10}{x ^{2} - 1}