What is the domain of f(x)=sqrt(16+x^2)-sqrt(x+1) ?

The domain of f(x)=sqrt(16+x^2)-sqrt(x+1) is x>=-1

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domain of f(x)=sqrt(16+x^2)-sqrt(x+1)

domain

f (x) = 16 + x^{2} - x + 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

f (x) = - 2^{x} + 1

f (x) = \frac{x ^{2}}{x ^{2} - 9}

f (x) = x^{2} - 4 x + 1, x < 2

f (x) = \frac{8 x + 3}{8 - 3 x}

f (x) = 100 x

What is the domain of f(x)=sqrt(16+x^2)-sqrt(x+1) ?
The domain of f(x)=sqrt(16+x^2)-sqrt(x+1) is x>=-1