What is the domain of f(x)= 1/(ln(2x-1)) ?

The domain of f(x)= 1/(ln(2x-1)) is 1/2 1

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domain of f(x)= 1/(ln(2x-1))

domain

f (x) = \frac{1}{ln ( 2 x - 1 )}

\frac{1}{2} < x < 1 or x > 1

Interval Notation

(\frac{1}{2}, 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x > \frac{1}{2}

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

\frac{1}{2} < x < 1 or x > 1

f (x) = y - 6 = 4 (x + 5)

f (x) = - (\frac{1}{3})^{x} + 2

(2 x - 6) (x - 4)

2 (x - 3)^{2} - 5

6 x + 12

What is the domain of f(x)= 1/(ln(2x-1)) ?
The domain of f(x)= 1/(ln(2x-1)) is 1/2 <x<1\lor x>1