What is the extreme f(x)=6sqrt(x)-2x ?

The extreme f(x)=6sqrt(x)-2x is Maximum(0,0),Maximum(9/4 , 9/2)

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extreme f(x)=6sqrt(x)-2x

extreme points

f (x) = 6 x - 2 x

Maximum (0, 0), Maximum (\frac{9}{4}, \frac{9}{2})

Solution steps

f^{'} (x) = \frac{3}{x} - 2

Find intervals:

Decreasing

: 0 \leq x < \frac{4}{9},

Increasing

: \frac{4}{9} < x < \infty

Plug

x = 0

into

6 x - 2 x : 0

Maximum (0, 0)

Plug

x = \frac{9}{4}

into

6 x - 2 x : \frac{9}{2}

Maximum (\frac{9}{4}, \frac{9}{2})

Maximum (0, 0), Maximum (\frac{9}{4}, \frac{9}{2})

f (x) = x^{3} - 7 x

f (x) = \frac{8 x ^{3} + 7 x ^{2} + 20}{2}

0.5 cos (16000 π t)

f (x) = (x - 12)^{2}

2 x - 7 y = 13

What is the extreme f(x)=6sqrt(x)-2x ?
The extreme f(x)=6sqrt(x)-2x is Maximum(0,0),Maximum(9/4 , 9/2)