What is the slope ofintercept 2x+5y+10=0 ?

The slope ofintercept 2x+5y+10=0 is y=-2/5 x-2

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slope ofintercept 2x+5y+10=0

slope intercept

2 x + 5 y + 10 = 0

y = - \frac{2}{5} x - 2

Solution steps

2 x + 5 y + 10 = 0

Convert to slope intercept form:

y = - \frac{2}{5} x - 2

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = - \frac{2}{5} x - 2

f (x) = x^{2} - 2 x - 24

(\frac{25}{2} x + 15) - 1

x^{\frac{5}{3}}

f (x) = \frac{( x - 1 )}{8}

2 cos (x)

What is the slope ofintercept 2x+5y+10=0 ?
The slope ofintercept 2x+5y+10=0 is y=-2/5 x-2