What is the inverse of f(x)=3(x-1)^2+1 ?

The inverse of f(x)=3(x-1)^2+1 is sqrt((x-1)/3)+1,-sqrt((x-1)/3)+1

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inverse of f(x)=3(x-1)^2+1

inverse

f (x) = 3 (x - 1)^{2} + 1

\frac{x - 1}{3} + 1, - \frac{x - 1}{3} + 1

Solution steps

y = 3 (x - 1)^{2} + 1

Replace

x

with

y

x = 3 (y - 1)^{2} + 1

Solve for

y, x = 3 (y - 1)^{2} + 1

\frac{x - 1}{3} + 1, - \frac{x - 1}{3} + 1

- x^{3} + 6 x^{2} - 15

6

\frac{1}{x ^{2} + 1} + 1

f (x) = - x^{2} - 2 x + 3

f (x) = e^{- 3 t}

What is the inverse of f(x)=3(x-1)^2+1 ?
The inverse of f(x)=3(x-1)^2+1 is sqrt((x-1)/3)+1,-sqrt((x-1)/3)+1