What is the inverse of f(x)=sqrt(x^3+2) ?

The inverse of f(x)=sqrt(x^3+2) is cube root of x^2-2

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inverse of f(x)=sqrt(x^3+2)

inverse

f (x) = x^{3} + 2

Solution steps

y = x^{3} + 2

Replace

x

with

y

x = y^{3} + 2

Solve for

y, x = y^{3} + 2

y = x^{2} (x^{2} - 9)^{\frac{1}{2}}

f (x) = 16 - x^{8}

f (x) = e^{2 (x - 3)^{3} l n ∣ x - 3 ∣}

f (x) = \frac{x ^{2} - 9}{x - 3}

What is the inverse of f(x)=sqrt(x^3+2) ?
The inverse of f(x)=sqrt(x^3+2) is cube root of x^2-2