What is the domain of sqrt(2-(x^2-x)) ?

The domain of sqrt(2-(x^2-x)) is -1<= x<= 2

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domain of sqrt(2-(x^2-x))

domain

2 - (x^{2} - x)

- 1 \leq x \leq 2

Interval Notation

[- 1, 2]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 2

The function domain

- 1 \leq x \leq 2

y = x^{2} + x - 2

4 x^{3} - 12 x

f (x) = \frac{1}{z - 7} - \frac{1}{z}

1 + x^{2}

(- 4, 3), (3, - 4)

What is the domain of sqrt(2-(x^2-x)) ?
The domain of sqrt(2-(x^2-x)) is -1<= x<= 2