What is the critical f(x)=(x^2-9)/(x^2+6) ?

The critical f(x)=(x^2-9)/(x^2+6) is x=0

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critical f(x)=(x^2-9)/(x^2+6)

critical points

f (x) = \frac{x ^{2} - 9}{x ^{2} + 6}

x = 0

Solution steps

\frac{x ^{2} - 9}{x ^{2} + 6}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 9}{x ^{2} + 6} : - \infty < x < \infty

All critical points are in domain

x = 0

3 \cdot 2^{x - 4} - 5

f (x) = \frac{( 1 - x )}{2 x - 1}

x^{2} - 6 x - 1

lo g_{5} (x + 2)

\frac{x ^{2} + x - 6}{x - 3}

What is the critical f(x)=(x^2-9)/(x^2+6) ?
The critical f(x)=(x^2-9)/(x^2+6) is x=0