What is the inverse of f(x)=(4/3)^{x-2} ?

The inverse of f(x)=(4/3)^{x-2} is (ln(x))/(ln(4/3))+2

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inverse of f(x)=(4/3)^{x-2}

inverse

f (x) = (\frac{4}{3})^{x - 2}

\frac{ln ( x )}{ln ( \frac{4}{3} )} + 2

Solution steps

y = (\frac{4}{3})^{x - 2}

Replace

x

with

y

x = (\frac{4}{3})^{y - 2}

Solve for

y, x = (\frac{4}{3})^{y - 2}

\frac{ln ( x )}{ln ( \frac{4}{3} )} + 2

f (x) = - sin (x - 4) - 5

(- 4, - 7), (- 22, - 87)

f (x) = 3 x^{2} + 7

(2 - 7 x)^{3}

f (x) = (x + 2) (x - 8)

What is the inverse of f(x)=(4/3)^{x-2} ?
The inverse of f(x)=(4/3)^{x-2} is (ln(x))/(ln(4/3))+2