What is the inverse of f(x)= 1/(sqrt(-2x)) ?

The inverse of f(x)= 1/(sqrt(-2x)) is -1/(2x^2)

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inverse of f(x)= 1/(sqrt(-2x))

inverse

f (x) = \frac{1}{- 2 x}

- \frac{1}{2 x ^{2}}

Solution steps

y = \frac{1}{- 2 x}

Replace

x

with

y

x = \frac{1}{- 2 y}

Solve for

y, x = \frac{1}{- 2 y}

- \frac{1}{2 x ^{2}}

y = - x

3 x + 6 y = 42

- \frac{3}{2 t ^{(\frac{3}{2})}}

6 x - 15 y = 135

f (x) = \frac{x ^{2} - x + 8}{x - 3}

What is the inverse of f(x)= 1/(sqrt(-2x)) ?
The inverse of f(x)= 1/(sqrt(-2x)) is -1/(2x^2)