What is the domain of f(x)=arcsin(6x^2-1+|x|) ?

The domain of f(x)=arcsin(6x^2-1+|x|) is -1/2 <= x<= 1/2

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domain of f(x)=arcsin(6x^2-1+|x|)

domain

f (x) = arcsin (6 x^{2} - 1 + ∣ x ∣)

- \frac{1}{2} \leq x \leq \frac{1}{2}

Interval Notation

[- \frac{1}{2}, \frac{1}{2}]

Solution steps

Find known functions domain restrictions:

- \frac{1}{2} \leq x \leq \frac{1}{2}

The function domain

- \frac{1}{2} \leq x \leq \frac{1}{2}

f (x) = - \frac{3}{x + 2} - 1

f (x) = \frac{2 x + 1}{x - 3}

1200 + 400 cos (\frac{π t}{3})

f (x) = x^{2} - 10 x + 21

9 x^{6} - x^{5} - 2 x^{3} + 2

What is the domain of f(x)=arcsin(6x^2-1+|x|) ?
The domain of f(x)=arcsin(6x^2-1+|x|) is -1/2 <= x<= 1/2