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Popular >

midpoint (-1,1),(7,-4)

Solution

midpoint

(- 1, 1), (7, - 4)

Solution

(3, - \frac{3}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 1, 1), (x_{2}, y_{2}) = (7, - 4)

= (\frac{7 - 1}{2}, \frac{- 4 + 1}{2})

Refine

= (3, - \frac{3}{2})

Popular Examples

perpendicular y= 1/4 x perpendicular

y = \frac{1}{4} x

domain of \sqrt[6]{x^5}domain

domain of x^2+3x-4 domain

x^{2} + 3 x - 4

domain of f(x)=(x^4)/(x^2+x-42)domain

f (x) = \frac{x ^{4}}{x ^{2} + x - 42}

asymptotes of (x^2-4)/(x^2-5x+6)asymptotes

\frac{x ^{2} - 4}{x ^{2} - 5 x + 6}

Frequently Asked Questions (FAQ)

What is the midpoint (-1,1),(7,-4) ?
The midpoint (-1,1),(7,-4) is (3,-3/2)