What is the domain of f(x)=(x+6)/(sqrt(x^2-3x-4)) ?

The domain of f(x)=(x+6)/(sqrt(x^2-3x-4)) is x 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(x+6)/(sqrt(x^2-3x-4))

domain

f (x) = \frac{x + 6}{x ^{2} - 3 x - 4}

x < - 1 or x > 4

Interval Notation

(- \infty, - 1) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 4

Find undefined (singularity) points:

x = 4, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 4

f (x) = 0.2 (x - 2) (x + 1) (x - 5)

(- 3, 4), (0, - 3)

f (x) = 3 x x

f (x) = x - 5

\frac{x - 2}{x ^{2} + 4 x + 4}

What is the domain of f(x)=(x+6)/(sqrt(x^2-3x-4)) ?
The domain of f(x)=(x+6)/(sqrt(x^2-3x-4)) is x<-1\lor x>4