What is the inverse of f(x)= 1/6 x^3-3 ?

The inverse of f(x)= 1/6 x^3-3 is cube root of 6x+18

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inverse of f(x)= 1/6 x^3-3

inverse

f (x) = \frac{1}{6} x^{3} - 3

Solution steps

y = \frac{1}{6} x^{3} - 3

Replace

x

with

y

x = \frac{1}{6} y^{3} - 3

Solve for

y, x = \frac{1}{6} y^{3} - 3

f (x) = \frac{- 13}{( 4 + x ) ^{2}}

\frac{x ^{2} + x - 20}{5 x + 25}

20 x + 7 y = 19

7 y = 1

What is the inverse of f(x)= 1/6 x^3-3 ?
The inverse of f(x)= 1/6 x^3-3 is cube root of 6x+18