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Popular >

distance (1,5),(7,13)

Solution

distance

(1, 5), (7, 13)

Solution

10

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(1, 5)

and

(7, 13)

is

= (7 - 1)^{2} + (13 - 5)^{2}

Simplify

= 10

Popular Examples

domain of f(x)=(x^2-6x)^{1/4}domain

f (x) = (x^{2} - 6 x)^{\frac{1}{4}}

domain of (x^3-x^2-2x)/(-3x^2+27)domain

\frac{x ^{3} - x ^{2} - 2 x}{- 3 x ^{2} + 27}

line (2,1),(5,7)line

(2, 1), (5, 7)

line m=infinity ,(3,2)line

m = \infty, (3, 2)

slope of f(x)= 4/5 x-4 slope

f (x) = \frac{4}{5} x - 4

Frequently Asked Questions (FAQ)

What is the distance (1,5),(7,13) ?
The distance (1,5),(7,13) is 10