What is the inverse of f(x)=(2+sqrt((x+6)^2))/(3-x) ?

The inverse of f(x)=(2+sqrt((x+6)^2))/(3-x) is (3x+4)/(x-1),(3x-8)/(x+1)

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inverse of f(x)=(2+sqrt((x+6)^2))/(3-x)

inverse

f (x) = \frac{2 + ( x + 6 ) ^{2}}{3 - x}

\frac{3 x + 4}{x - 1}, \frac{3 x - 8}{x + 1}

Solution steps

y = \frac{2 + ( x + 6 ) ^{2}}{3 - x}

Replace

x

with

y

x = \frac{2 + ( y + 6 ) ^{2}}{3 - y}

Solve for

y, x = \frac{2 + ( y + 6 ) ^{2}}{3 - y}

\frac{3 x + 4}{x - 1}, \frac{3 x - 8}{x + 1}

f (x) = - (x + 2)^{2} + 4

\frac{x ^{2} - 9}{x ^{3} - 2 x ^{2} - 15 x}

f (x) = \frac{3 x ^{2}}{2 x ^{2} - 32}

y = \frac{4 x - 2}{3 x + 1}

f (x) = \frac{1}{2} cos (2 x)

What is the inverse of f(x)=(2+sqrt((x+6)^2))/(3-x) ?
The inverse of f(x)=(2+sqrt((x+6)^2))/(3-x) is (3x+4)/(x-1),(3x-8)/(x+1)