What is the domain of f(x)= 1/(sqrt(x^2-5x+6)) ?

The domain of f(x)= 1/(sqrt(x^2-5x+6)) is x 3

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domain of f(x)= 1/(sqrt(x^2-5x+6))

domain

f (x) = \frac{1}{x ^{2} - 5 x + 6}

x < 2 or x > 3

Interval Notation

(- \infty, 2) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 2 or x \geq 3

Find undefined (singularity) points:

x = 3, x = 2

Combine real regions and undefined points for final function domain

x < 2 or x > 3

lo g_{3} (x - 1) + 3

- \frac{1}{5} cos (\frac{1}{5} x)

∣ sin (4 x) + 5 cos (4 x) ∣

\frac{1}{e ^{x} + 1}

f (x) = 18 x^{4} - 108 x^{2}

What is the domain of f(x)= 1/(sqrt(x^2-5x+6)) ?
The domain of f(x)= 1/(sqrt(x^2-5x+6)) is x<2\lor x>3