What is the domain of f(x)=(5x-3)/(sqrt(36-x^2)) ?

The domain of f(x)=(5x-3)/(sqrt(36-x^2)) is -6<x<6

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domain of f(x)=(5x-3)/(sqrt(36-x^2))

domain

f (x) = \frac{5 x - 3}{36 - x ^{2}}

- 6 < x < 6

Interval Notation

(- 6, 6)

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 6

Find undefined (singularity) points:

x = 6, x = - 6

Combine real regions and undefined points for final function domain

- 6 < x < 6

y = e^{- x}

\frac{5 x - 8}{5 x}

f (x) = x^{2} + 10

(7.5) (3.2)

3 - 4 x

What is the domain of f(x)=(5x-3)/(sqrt(36-x^2)) ?
The domain of f(x)=(5x-3)/(sqrt(36-x^2)) is -6<x<6