What is the inverse of f(x)=4pir^2 ?

The inverse of f(x)=4pir^2 is (sqrt(pi)sqrt(r))/(2pi),-(sqrt(pi)sqrt(r))/(2pi)

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inverse of f(x)=4pir^2

inverse

f (x) = 4 π r^{2}

\frac{π r}{2 π}, - \frac{π r}{2 π}

Solution steps

x = 4 π r^{2}

Replace

r

with

x

r = 4 π x^{2}

Solve for

x, r = 4 π x^{2}

\frac{π r}{2 π}, - \frac{π r}{2 π}

\frac{- 2 x + 63}{x ( x + 9 )}

f (x) = - \frac{1}{x}

f (x) = 10 e^{0.1 x}

y = 3 x + 77

f (x) = 2 (x - 1)^{2} + 6

What is the inverse of f(x)=4pir^2 ?
The inverse of f(x)=4pir^2 is (sqrt(pi)sqrt(r))/(2pi),-(sqrt(pi)sqrt(r))/(2pi)