What is the domain of f(x)=e^{(x-1)/(x^2-1)} ?

The domain of f(x)=e^{(x-1)/(x^2-1)} is x 1

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domain of f(x)=e^{(x-1)/(x^2-1)}

domain

f (x) = e^{\frac{x - 1}{x ^{2} - 1}}

x < - 1 or - 1 < x < 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (- 1, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1, x = - 1

The function domain

x < - 1 or - 1 < x < 1 or x > 1

f (x) = 9 - x^{2}

f (x) = x^{4} + 5 x^{3} - 9 x^{2} - 45 x

f (x) = \frac{6 + x}{6 - x}

f (x) = \frac{1}{2} e^{x + 1} - 2

f (x) = x^{4} - 16 x^{3} + 22 x^{2}

What is the domain of f(x)=e^{(x-1)/(x^2-1)} ?
The domain of f(x)=e^{(x-1)/(x^2-1)} is x<-1\lor-1<x<1\lor x>1