What is the domain of y=sqrt(x^2-9) ?

The domain of y=sqrt(x^2-9) is x = 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of y=sqrt(x^2-9)

domain

y = x^{2} - 9

x \leq - 3 or x \geq 3

Interval Notation

(- \infty, - 3] \cup [3, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 3 or x \geq 3

The function domain

x \leq - 3 or x \geq 3

f (x) = - x^{2} + 4 x + 1

ln (5 x)

f (x) = - 4 x - 1

4 - 7 x

f (x) = x + 6

What is the domain of y=sqrt(x^2-9) ?
The domain of y=sqrt(x^2-9) is x<=-3\lor x>= 3