What is the domain of f(x)= 1/x+1/(x-1)+1/(x-2) ?

The domain of f(x)= 1/x+1/(x-1)+1/(x-2) is x 2

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domain of f(x)= 1/x+1/(x-1)+1/(x-2)

domain

f (x) = \frac{1}{x} + \frac{1}{x - 1} + \frac{1}{x - 2}

x < 0 or 0 < x < 1 or 1 < x < 2 or x > 2

Interval Notation

(- \infty, 0) \cup (0, 1) \cup (1, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

x = 0, x = 1, x = 2

The function domain

x < 0 or 0 < x < 1 or 1 < x < 2 or x > 2

f (x) = 6 x - x^{2}

- x^{3} + 8 x^{2} - 15 x

f (x) = (x - 2)^{2} + 3

(- 2, - 6), (4, 6)

y = 8 x - 7

What is the domain of f(x)= 1/x+1/(x-1)+1/(x-2) ?
The domain of f(x)= 1/x+1/(x-1)+1/(x-2) is x<0\lor 0<x<1\lor 1<x<2\lor x>2