What is the extreme f(x)=x^3-3x^2-9x-4 ?

The extreme f(x)=x^3-3x^2-9x-4 is Maximum(-1,1),Minimum(3,-31)

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extreme f(x)=x^3-3x^2-9x-4

extreme points

f (x) = x^{3} - 3 x^{2} - 9 x - 4

Maximum (- 1, 1), Minimum (3, - 31)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x - 4 : 1

Maximum (- 1, 1)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x - 4 : - 31

Minimum (3, - 31)

Maximum (- 1, 1), Minimum (3, - 31)

3 x^{2}

arcsin (tan (x))

f (x) = e^{x + 3} + 4

f (x) = \frac{x - 6}{4}

f (x) = \frac{x + 8}{x - 5}

What is the extreme f(x)=x^3-3x^2-9x-4 ?
The extreme f(x)=x^3-3x^2-9x-4 is Maximum(-1,1),Minimum(3,-31)