What is the perpendicular-6*sqrt(3)*x+6+2*sqrt(3)*pi ?

The perpendicular-6*sqrt(3)*x+6+2*sqrt(3)*pi is y= 1/(6sqrt(3))x+b

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perpendicular-6sqrt(3)x+6+2sqrt(3)pi

perpendicular

- 6 \cdot 3 \cdot x + 6 + 2 \cdot 3 \cdot π

y = \frac{1}{6 3} x + b

Solution steps

Find the slope of

y = - 63 x + 6 + 23 π : m = - 63

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{6 3}

Line with slope m=

\frac{1}{6 3} : y = \frac{1}{6 3} x + b

y = \frac{1}{6 3} x + b

f (x) = - \frac{3}{2} tan (x - \frac{π}{6})

(- 3.5) (4.4)

f (x) = \frac{5}{x} + 2

f (x) = 4 - x^{2}

f (x) = - \frac{1}{64} (x - 6)^{3} + 3

What is the perpendicular-6*sqrt(3)*x+6+2*sqrt(3)*pi ?
The perpendicular-6*sqrt(3)*x+6+2*sqrt(3)*pi is y= 1/(6sqrt(3))x+b