What is the range of (3x+8)/(x+3) ?

The range of (3x+8)/(x+3) is f(x) 3

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range of (3x+8)/(x+3)

range

\frac{3 x + 8}{x + 3}

f (x) < 3 or f (x) > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

The function range is the combined domain of the inverse functions

Find the inverse function(s) of:

\frac{3 x + 8}{x + 3}

Inverse of

\frac{3 x + 8}{x + 3} : \frac{8 - 3 x}{x - 3}

\frac{8 - 3 x}{x - 3}

Find the domain of each inverse function

Domain of

\frac{8 - 3 x}{x - 3} : x < 3 or x > 3

Combine the intervals

f (x) < 3 or f (x) > 3

y = - 2 lo g_{3} (x) - 5

\frac{7}{x - 4}

f (x) = \frac{x ^{2} - 9}{2}

(0, - 1), (3, 0.5)

f (x) = - 2 sin (x)

What is the range of (3x+8)/(x+3) ?
The range of (3x+8)/(x+3) is f(x)<3\lor f(x)>3