What is the extreme f(x)=x^3-27x+57 ?

The extreme f(x)=x^3-27x+57 is Maximum(-3,111),Minimum(3,3)

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extreme f(x)=x^3-27x+57

extreme points

f (x) = x^{3} - 27 x + 57

Maximum (- 3, 111), Minimum (3, 3)

Solution steps

f^{'} (x) = 3 x^{2} - 27

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{3} - 27 x + 57 : 111

Maximum (- 3, 111)

Plug

x = 3

into

x^{3} - 27 x + 57 : 3

Minimum (3, 3)

Maximum (- 3, 111), Minimum (3, 3)

(6, - 2), (- 2, 3)

f (x) = \frac{x}{12}

f (x) = - \frac{3}{4} x^{4} - x^{3} + 3 x^{2}

f (x) = ln (ln (ln (4 x)))

\frac{x ^{3} + 4 x ^{2}}{6 x ^{2} - 1}

What is the extreme f(x)=x^3-27x+57 ?
The extreme f(x)=x^3-27x+57 is Maximum(-3,111),Minimum(3,3)