What is the inverse of f(x)=6.3(b+2)^{3/2} ?

The inverse of f(x)=6.3(b+2)^{3/2} is (100^{1/3}b^{2/3})/(3*147^{1/3)}-2

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inverse of f(x)=6.3(b+2)^{3/2}

inverse

f (x) = 6.3 (b + 2)^{\frac{3}{2}}

\frac{10 0 ^{\frac{1}{3}} b ^{\frac{2}{3}}}{3 \cdot 14 7 ^{\frac{1}{3}}} - 2

Solution steps

y = 6.3 (b + 2)^{\frac{3}{2}}

Replace

b

with

y

b = 6.3 (y + 2)^{\frac{3}{2}}

Solve for

y, b = 6.3 (y + 2)^{\frac{3}{2}}

\frac{10 0 ^{\frac{1}{3}} b ^{\frac{2}{3}}}{3 \cdot 14 7 ^{\frac{1}{3}}} - 2

- \frac{2}{x}

(1, 6), (5, - 2)

f (x) = \frac{x ^{2} - 4}{x ^{2} - x - 6}

f (x) = x^{2} - x + 3

f (x) = (7 - x)^{2}

What is the inverse of f(x)=6.3(b+2)^{3/2} ?
The inverse of f(x)=6.3(b+2)^{3/2} is (100^{1/3}b^{2/3})/(3*147^{1/3)}-2