What is the perpendicular y=18x+2,(1,-5) ?

The perpendicular y=18x+2,(1,-5) is y=-1/18 x-89/18

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perpendicular y=18x+2,(1,-5)

perpendicular

y = 18 x + 2, (1, - 5)

y = - \frac{1}{18} x - \frac{89}{18}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 18 x + 2

that passes through

(1, - 5)

Find the slope of

y = 18 x + 2 : m = 18

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{18}

Find the line with slope m=

- \frac{1}{18}

and passing through

(1, - 5) : y = - \frac{1}{18} x - \frac{89}{18}

y = - \frac{1}{18} x - \frac{89}{18}

(\frac{1}{x})^{2} - 9

f (x) = \frac{x ^{2} + 3 x - 2}{x ^{2} - 5 x + 6}

f (x) = \frac{( 3 x )}{7 x + 14}

f (x) = 2 x^{3} - 9 x^{2} - 24 x + 20

f (x) = 3 x^{3} + 2

What is the perpendicular y=18x+2,(1,-5) ?
The perpendicular y=18x+2,(1,-5) is y=-1/18 x-89/18