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Popular >

midpoint (-12,6),(-8,-13)

Solution

midpoint

(- 12, 6), (- 8, - 13)

Solution

(- 10, - \frac{7}{2})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (- 12, 6), (x_{2}, y_{2}) = (- 8, - 13)

= (\frac{- 8 - 12}{2}, \frac{- 13 + 6}{2})

Refine

= (- 10, - \frac{7}{2})

Popular Examples

parallel y= 5/2 x+5 parallel

y = \frac{5}{2} x + 5

domain of f(x)=sqrt(x^3-x)domain

f (x) = x^{3} - x

distance (5,-6),(8,-9)distance

(5, - 6), (8, - 9)

inverse of f(x)=sqrt(x)+12 inverse

f (x) = x + 12

domain of f(x)= 1/(x+4)domain

f (x) = \frac{1}{x + 4}

Frequently Asked Questions (FAQ)

What is the midpoint (-12,6),(-8,-13) ?
The midpoint (-12,6),(-8,-13) is (-10,-7/2)