What is the inverse of f(x)=(x-3)^2-7 ?

The inverse of f(x)=(x-3)^2-7 is sqrt(x+7)+3,-sqrt(x+7)+3

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inverse of f(x)=(x-3)^2-7

inverse

f (x) = (x - 3)^{2} - 7

x + 7 + 3, - x + 7 + 3

Solution steps

y = (x - 3)^{2} - 7

Replace

x

with

y

x = (y - 3)^{2} - 7

Solve for

y, x = (y - 3)^{2} - 7

x + 7 + 3, - x + 7 + 3

f (x) = \frac{1}{x ^{2} - 5 x + 6}

y = - 2 x + 2

f (x) = \frac{3 x ^{2} + 5 x - 7}{x ^{2} - 3}

f (x) = \frac{x ^{2} - 4 x + 3}{x ^{2} - 1}

f (x) = 5 x - 12 = 0

What is the inverse of f(x)=(x-3)^2-7 ?
The inverse of f(x)=(x-3)^2-7 is sqrt(x+7)+3,-sqrt(x+7)+3