What is the critical f(x)=(x-1)/(x^2+3) ?

The critical f(x)=(x-1)/(x^2+3) is x=-1,x=3

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critical f(x)=(x-1)/(x^2+3)

critical points

f (x) = \frac{x - 1}{x ^{2} + 3}

x = - 1, x = 3

Solution steps

\frac{x - 1}{x ^{2} + 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x - 1}{x ^{2} + 3} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 3

y - 1 = (x - 2)^{2}

f (x) = - 16 x^{2} + 48 x + 160

(x - 1)^{2}

\frac{4 x + 9}{3 x - 6}

t^{2}

What is the critical f(x)=(x-1)/(x^2+3) ?
The critical f(x)=(x-1)/(x^2+3) is x=-1,x=3