What is the domain of f(x)=((x+2)(x-1))/((x-3)^2) ?

The domain of f(x)=((x+2)(x-1))/((x-3)^2) is x 3

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domain of f(x)=((x+2)(x-1))/((x-3)^2)

domain

f (x) = \frac{( x + 2 ) ( x - 1 )}{( x - 3 ) ^{2}}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

f (x) = 2 x - 4

f (x) = - 3 ∣ 7 - 2 x ∣ + 4

x^{2} - 3

f (x) = \frac{1}{x + 2} - 2

8 x - 6 y = 8

What is the domain of f(x)=((x+2)(x-1))/((x-3)^2) ?
The domain of f(x)=((x+2)(x-1))/((x-3)^2) is x<3\lor x>3