What is the domain of 1/(sqrt(x^2-4x)) ?

The domain of 1/(sqrt(x^2-4x)) is x 4

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domain of 1/(sqrt(x^2-4x))

domain

\frac{1}{x ^{2} - 4 x}

x < 0 or x > 4

Interval Notation

(- \infty, 0) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 4

Find undefined (singularity) points:

x = 4, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 4

f (x) = 2 x^{3} + 3 x^{2} - 36 x

f (x) = x + y = - 1

f (x) = \frac{x}{1 + x ^{2}}

x^{4} + 32 x^{2} + 256

f (x) = x x + 1

What is the domain of 1/(sqrt(x^2-4x)) ?
The domain of 1/(sqrt(x^2-4x)) is x<0\lor x>4