What is the domain of f(x)=(2x)/(x^2-25) ?

The domain of f(x)=(2x)/(x^2-25) is x 5

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domain of f(x)=(2x)/(x^2-25)

domain

f (x) = \frac{2 x}{x ^{2} - 25}

x < - 5 or - 5 < x < 5 or x > 5

Interval Notation

(- \infty, - 5) \cup (- 5, 5) \cup (5, \infty)

Solution steps

Find undefined (singularity) points:

x = 5, x = - 5

The function domain

x < - 5 or - 5 < x < 5 or x > 5

f (x) = \frac{( 5 x + 2 )}{x}

f (x) = \frac{12 x + 35}{x ^{2} + 7 x}

(\frac{4}{10})^{x}

f (x) = 2 x^{3} - 96 x + 42

f (x) = \frac{( x + 2 )}{x ^{2} + 4 x - 5}

What is the domain of f(x)=(2x)/(x^2-25) ?
The domain of f(x)=(2x)/(x^2-25) is x<-5\lor-5<x<5\lor x>5