What is the inverse of f(x)=3ln(4x-1)+9 ?

The inverse of f(x)=3ln(4x-1)+9 is (e^{(x-9)/3}+1)/(4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=3ln(4x-1)+9

inverse

f (x) = 3 ln (4 x - 1) + 9

\frac{e ^{\frac{x - 9}{3}} + 1}{4}

Solution steps

y = 3 ln (4 x - 1) + 9

Replace

x

with

y

x = 3 ln (4 y - 1) + 9

Solve for

y, x = 3 ln (4 y - 1) + 9

\frac{e ^{\frac{x - 9}{3}} + 1}{4}

\frac{e ^{x} - e ^{- x}}{6}

f (x) = 2 x^{4}

\frac{3 x + 2}{9 x - 4}

f (x) = x^{2} + 6 x - 16

\frac{x ^{2} + 3 x}{x ^{2} - x}

What is the inverse of f(x)=3ln(4x-1)+9 ?
The inverse of f(x)=3ln(4x-1)+9 is (e^{(x-9)/3}+1)/(4)