What is the perpendicular y=3x-2,(-1,3) ?

The perpendicular y=3x-2,(-1,3) is y=-1/3 x+8/3

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perpendicular y=3x-2,(-1,3)

perpendicular

y = 3 x - 2, (- 1, 3)

y = - \frac{1}{3} x + \frac{8}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x - 2

that passes through

(- 1, 3)

Find the slope of

y = 3 x - 2 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(- 1, 3) : y = - \frac{1}{3} x + \frac{8}{3}

y = - \frac{1}{3} x + \frac{8}{3}

(- 8, 2), (- 8 + 43, 6)

\frac{x ( 2 x ^{2} - 3 x + 1 )}{x ^{3} + 1}

y = x + 1

f (x) = \frac{x + 2}{x}

What is the perpendicular y=3x-2,(-1,3) ?
The perpendicular y=3x-2,(-1,3) is y=-1/3 x+8/3