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Popular >

f(x)=x^2-2x+2

Solution

f (x) = x^{2} - 2 x + 2

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq 1

Y Intercepts : (0, 2)

Vertex : Minimum (1, 1)

Inverse : 1 + x - 1, 1 - x - 1

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [1, \infty)

Solution steps

Domain of

x^{2} - 2 x + 2 : - \infty < x < \infty

Range of

x^{2} - 2 x + 2 : f (x) \geq 1

Axis interception points of

x^{2} - 2 x + 2 :

Y Intercepts

: (0, 2)

Vertex of

x^{2} - 2 x + 2 :

Minimum

(1, 1)

Inverse of

x^{2} - 2 x + 2 : 1 + x - 1, 1 - x - 1

Popular Examples

inverse of f(x)=sqrt(x^2-4x)inverse

f (x) = x^{2} - 4 x

critical f(x)=(x^2-1)^2 critical points

f (x) = (x^{2} - 1)^{2}

intercepts of f(x)=8x-6y=-2 intercepts

f (x) = 8 x - 6 y = - 2

inverse of (x+1)^2+1 inverse

(x + 1)^{2} + 1

range of sqrt(-x)-3 range

- x - 3

Frequently Asked Questions (FAQ)

What is the f(x)=x^2-2x+2 ?
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