What is the asymptotes of f(x)=(x^2+8x-4)/(-2x-4) ?

The asymptotes of f(x)=(x^2+8x-4)/(-2x-4) is Vertical: x=-2,Slant: y=-1/2 x-3

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asymptotes of f(x)=(x^2+8x-4)/(-2x-4)

asymptotes

f (x) = \frac{x ^{2} + 8 x - 4}{- 2 x - 4}

Vertical : x = - 2, Slant : y = - \frac{1}{2} x - 3

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 8 x - 4}{- 2 x - 4} : x = - 2

Horizontal Asymptotes of

\frac{x ^{2} + 8 x - 4}{- 2 x - 4} :

None

Slant Asymptotes of

\frac{x ^{2} + 8 x - 4}{- 2 x - 4} : y = - \frac{1}{2} x - 3

Vertical : x = - 2, Slant : y = - \frac{1}{2} x - 3

a

f (x) = \frac{x}{x ^{2} - 1}

x - 5 + 3

f (x) = \frac{x + 5}{- 4 x}

f (x) = \frac{1}{1 - x}

What is the asymptotes of f(x)=(x^2+8x-4)/(-2x-4) ?
The asymptotes of f(x)=(x^2+8x-4)/(-2x-4) is Vertical: x=-2,Slant: y=-1/2 x-3