What is the critical f(x)=2x^3-3x^2-36x ?

The critical f(x)=2x^3-3x^2-36x is x=-2,x=3

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critical f(x)=2x^3-3x^2-36x

critical points

f (x) = 2 x^{3} - 3 x^{2} - 36 x

x = - 2, x = 3

Solution steps

2 x^{3} - 3 x^{2} - 36 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 3

Identify critical points not in

f (x)

domain

Domain of

2 x^{3} - 3 x^{2} - 36 x : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 3

f (x) = 3 x + 3

f (x) = - 1

f (x) = - x + 2

y = 2 x^{2} + 3

f (x) = - (x - 4)^{2} + 1

What is the critical f(x)=2x^3-3x^2-36x ?
The critical f(x)=2x^3-3x^2-36x is x=-2,x=3